ch05-p008 - 8. Since the tire remains stationary, by...

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net, net, 0 cos cos 0s i n s i n xC A yA C B FF F F F φθ θφ ==− ==+ ¦ ¦ To solve for B F , we first compute . φ With 220 N A F = , 170 N C F = and 47 , θ we get cos (220 N)cos47.0 cos 0.883 28.0 170 N A C F F φφ ° == = ¡ Substituting the value into the second force equation, we find sin sin (220 N)sin 47.0 (170 N)sin 28.0 241 N.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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