(b) Since the customer is being pulled down with an acceleration of 2customerˆ1.24( 12.15 m/s )j,ag′==−GGthe acceleration of the coin with respect to the customer is 222relcoincustomerˆˆˆ( 9.8 m/s )j ( 12.15 m/s )j( 2.35 m/s )j.aaa′=−=−−−=+G(c) The time it takes for the coin to reach the ceiling is 2rel(2.20m)1.37 s.2.35 m/shta=(d) Since gravity is the only force acting on the coin, the actual force on the coin is 323coincoin(0.567 10kg)( 9.8 m/s )j
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.