18. We note that the rope is 22.0° from vertical – and therefore 68.0° from horizontal. (a) With T= 760 N, then its components are ˆˆˆˆcos 68.0 i+ sin 68.0 j=(285N)i+(705N) jTTT=°°G.(b) No longer in contact with the cliff, the only other force on Tarzan is due to earth’s gravity (his weight). Thus, netˆˆˆ(285 N) i+(705 N) j(820 N) j(285N)i(115 N) j.FTW=+ =−=−GGG(c) In a manner that is efficiently implemented on a vector-capable calculator, we convert from rectangular (x
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.