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19. (a) Since the acceleration of the block is zero, the components of the Newton’s
second law equation yield
T
–
mg
sin
θ
= 0
F
N
–
mg
cos
= 0.
Solving the first equation for the tension in the string, we find
Tm
g
==
°
=
sin
.
.
85
9 8
30
42
2
kg
m / s
N .
b
gc
h
(b) We solve the second equation in part (a) for the normal force
F
N
:
()
2
cos
8.5 kg 9.8 m/s
cos 30
72 N .
N
Fm
g
°
=
(c) When the string is cut, it no longer exerts a force on the block and the block
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration

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