ch05-p030 - 30. The stopping force F and the path of the...

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30. The stopping force G F and the path of the car are horizontal. Thus, the weight of the car contributes only (via Eq. 5-12) to information about its mass ( m = W / g = 1327 kg). Our + x axis is in the direction of the car’s velocity, so that its acceleration (‘‘deceleration”) is negative-valued and the stopping force is in the – x direction: ˆ i FF =− G . (a) We use Eq. 2-16 and SI units (noting that v = 0 and v 0 = 40(1000/3600) = 11.1 m/s). () 2 2 22 0 0 (11.1 m/s) 2 1 5 m v vv a x a x =+Δ ¡ = − Δ which yields a = – 4.12 m/s 2 . Assuming there are no significant horizontal forces other than the stopping force, Eq. 5-1 leads to G G Fm a F = ¡ −= 1327 412 kg m s 2
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