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22
2
ˆˆ
ˆ
ˆ
[8.00 i 6.00(1.415) j] m/s
(8.00 m/s ) i (8.49 m/s )j.
a
=+
=
+
G
The angle
a
G
makes with +
x
is
2
11
2
8.49 m/s
tan
tan
46.7 .
8.00 m/s
y
a
x
a
a
θ
−−
§·
==
=
°
¨¸
©¹
(b) The velocity vector at
1.415 s
t
=
is
2
ˆ
ˆ
8.00(1.415) i 3.00(1.415) j m/s
(11.3 m/s) i (6.01m/s)j.
v
ªº
=
+
¬¼
G
Therefore, the angle
v
G
makes with +
x
is
6.01m/s
tan
tan
28.0 .
11.3 m/s
y
v
x
v
v
=
°
31. The acceleration vector as a function of time is
()
ˆ
ˆ
8.00 i 3.00
j m/s
(8.00 i 6.00 j) m/s .
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 Spring '08
 Any
 Physics, Acceleration, Force

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