34. (a) Using notation suitable to a vector capable calculator, the Fnet→= 0 condition becomes F1→+ F2→+ F3→= (6.00 ∠150º) + (7.00 ∠−60.0º) + F3→= 0 . Thus,F3→= (1.70 N) i^+ (3.06 N)j^.(b) A constant velocity condition requires zero acceleration, so the answer is the same.
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