mgFwsin.θ−=0This yields Fw= 68 N (uphill). (b) Given our coordinate choice, we have a=| a|= 1.0 m/s2. Newton’s second law mgFmawnow leads to Fw= 28 N (uphill). (c) Continuing with the forces as shown in our figure, the equation mgFmawwill lead to Fw= – 12 N when | a| = 2.0 m/s2. This simply tells us that the wind is opposite to the direction shown in our sketch; in other words, 12 NwF=Gdownhill.36. We label the 40 kg skier “
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