ch05-p039 - 39 The free-body diagram is shown below Let T...

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39. The free-body diagram is shown below. Let G T be the tension of the cable and mg G be the force of gravity. If the upward direction is positive, then Newton’s second law is T mg = ma , where a is the acceleration. Thus, the tension is T = m ( g + a ). We use constant acceleration kinematics (Table 2-1) to find the acceleration (where v = 0 is the final velocity,
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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