39. The free-body diagram is shown below. LetGTbe the tension of the cable and mgGbe the force of gravity. If the upward direction is positive, then Newton’s second law is T– mg= ma, where ais the acceleration. Thus, the tension is T= m(g+ a). We use constant acceleration kinematics (Table 2-1) to find the acceleration (where v= 0 is the final velocity,
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