42. (a) The term “deceleration” means the acceleration vector is in the direction opposite to the velocity vector (which the problem tells us is downward). Thus (with +yupward) the acceleration is a= +2.4 m/s2. Newton’s second law leads to TmgmamTga−=¡=+which yields
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.