ch05-p043 - 43 The mass of the bundle is m =(449 N(9.80...

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43. The mass of the bundle is m = (449 N)/(9.80 m/s 2 ) = 45.8 kg and we choose + y upward. (a) Newton’s second law, applied to the bundle, leads to 387 N 449 N 45.8 kg Tm gm a a −= ¡ = which yields a = –1.4 m/s 2 (or | a | = 1.4 m/s 2 ) for the acceleration. The minus sign in the result indicates the acceleration vector points down. Any downward acceleration of magnitude greater than this is also acceptable (since that would lead to even smaller
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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