ch05-p045 - 45. (a) The links are numbered from bottom to...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
45. (a) The links are numbered from bottom to top. The forces on the bottom link are the force of gravity mg G , downward, and the force G F 21 on of link 2, upward. Take the positive direction to be upward. Then Newton’s second law for this link is F 2on1 mg = ma . Thus, F 2on1 = m ( a + g ) = (0.100 kg) (2.50 m/s 2 + 9.80 m/s 2 ) = 1.23 N. (b) The forces on the second link are the force of gravity mg G , downward, the force G F 12 on of link 1, downward, and the force G F 32 on of link 3, upward. According to Newton’s third law 1on2 F G has the same magnitude as G F on . Newton’s second law for the second link is F 3on2 F 1on2 mg = ma , so F 3on2 = m ( a + g ) + F 1on2 = (0.100 kg) (2.50 m/s 2 + 9.80 m/s 2 ) + 1.23 N = 2.46 N. (c) Newton’s second for link 3 is F 4on3 F 2on3 mg = ma , so F 4on3 = m ( a + g ) + F 2on3 = (0.100 N) (2.50 m/s
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online