49. Using Eq. 4-26, the launch speed of the projectile is20(9.8 m/s )(69 m)26.52 m/ssin 2sin 2(53 )gRvθ===°.The horizontal and vertical components of the speed are 00cos(26.52 m/s)cos5315.96 m/ssin(26.52 m/s)sin5321.18 m/s.xyvv°=°=Since the acceleration is constant, we can use Eq. 2-16 to analyze the motion. The component of the acceleration in the horizontal direction is 222(15.96 m/s)40.7 m/s ,22(5.2 m)cos53xxvax=°and the force component is
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