53. The free-body diagrams for part (a) are shown below. GFis the applied force and Gfis the force exerted by block 1 on block 2. We note that GFis applied directly to block 1 and that block 2 exerts the force −Gfon block 1 (taking Newton’s third law into account).(a) Newton’s second law for block 1 is F– f= m1a, where ais the acceleration. The second law for block 2 is f= m2a. Since the blocks move together they have the same acceleration and the same symbol is used in both equations. From the second equation we obtain the expression a= f/m2, which we substitute into the first equation to get F– f= m1f/m2. Therefore, fFmmm=+=+=2
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.