ch05-p054 - m BC = 50.0 kg The magnitude of the...

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m C g T BC = m C a . This leads to T BC = 36.8 N. (b) We use Eq. 2-15 (choosing rightward as the + x direction): Δ x = 0 + 1 2 at 2 = 0.191 m. 54. (a) The net force on the system (of total mass M = 80.0 kg) is the force of gravity acting on the total overhanging mass (
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Unformatted text preview: m BC = 50.0 kg). The magnitude of the acceleration is therefore a = ( m BC g )/ M = 6.125 m/s 2 . Next we apply Newton’s second law to block C itself (choosing down as the + y direction) and obtain...
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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