ch05-p060 - 60. The motion of the man-and-chair is positive...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
2 T mg ma −= so that when a = 0, the tension is T = 466 N. (b) When a = +1.30 m/s 2 the equation in part (a) predicts that the tension will be 527 N T = . (c) When the man is not holding the rope (instead, the co-worker attached to the ground is pulling on the rope with a force equal to the tension T in it), there is only one contact point between the rope and the man-and-chair, and Newton’s second law now leads to T mg ma so that when a = 0, the tension is T = 931 N. (d) When a = +1.30 m/s 2 , the equation in (c) yields T = 1.05 × 10 3 N. (e) The rope comes into contact (pulling down in each case) at the left edge and the right edge of the pulley, producing a total downward force of magnitude 2
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online