2Tmgma−=so that when a= 0, the tension is T= 466 N. (b) When a= +1.30 m/s2the equation in part (a) predicts that the tension will be 527 NT=.(c) When the man is not holding the rope (instead, the co-worker attached to the ground is pulling on the rope with a force equal to the tension Tin it), there is only one contact point between the rope and the man-and-chair, and Newton’s second law now leads to Tmgmaso that when a= 0, the tension is T= 931 N. (d) When a= +1.30 m/s2, the equation in (c) yields T= 1.05 ×103N. (e) The rope comes into contact (pulling down in each case) at the left edge and the right edge of the pulley, producing a total downward force of magnitude 2
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