ch05-p062 - 62. The horizontal component of the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
62. The horizontal component of the acceleration is determined by the net horizontal force. (a) If the rate of change of the angle is 22 4 rad (2.00 10 ) /s (2.00 10 ) /s 3.49 10 rad/s 180 d dt θπ −− §· ° ° = × ¨¸ ° ©¹ , then, using cos x FF θ = , we find the rate of change of acceleration to be () 4 43 cos sin (20.0 N)sin 25.0 3.49 10 rad/s 5.00 kg 5.90 10 m/s . x da dF F d dt dt m m dt θθ ° == = × =− × (b) If the rate of change of the angle is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online