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62. The horizontal component of the acceleration is determined by the net horizontal
force.
(a) If the rate of change of the angle is
22
4
rad
(2.00 10 ) /s
(2.00 10 ) /s
3.49 10 rad/s
180
d
dt
θπ
−−
−
§·
=×
°
°
⋅
=
×
¨¸
°
©¹
,
then, using
cos
x
FF
θ
=
, we find the rate of change of acceleration to be
()
4
43
cos
sin
(20.0 N)sin 25.0
3.49 10 rad/s
5.00 kg
5.90 10
m/s .
x
da
dF
F
d
dt
dt
m
m
dt
θθ
−
−
°
==
−
=
−
×
=−
×
(b) If the rate of change of the angle is
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration, Force

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