()23121221022(2.80 kg)(9.80 m/s )0.200 kg/s0.653 m/s .()(2.80 kg 1.30 kg)dmm gdmdadadtdm dtmmdt==−=−−=++(b) At 3.00 s,t=1101(/)1.30 kg ( 0.200 kg/s)(3.00 s)0.700 kg,mmdm dt t=+=+−=and the rate of change of acceleration is 231122(2.80 kg)(9.80 m/s )0.200 kg/s0.896 m/s .()(2.80 kg 0.700 kg)dmm gdmdadadtdm dtmmdt−=−−=(c) The acceleration reaches its maximum value when 010(/)1.30 kg ( 0.200 kg/s) ,mmdm dt tt+=+−or6.50 s.t=63. The free-body diagrams for 1mand 2mare shown in the figures below. The only forces on the blocks are the upward
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.