ch05-p065 - system = 24.0 kg). This yields an acceleration...

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65. First we analyze the entire system with “clockwise” motion considered positive (that is, downward is positive for block C , rightward is positive for block B , and upward is positive for block A ): m C g m A g = Ma (where M = mass of the
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Unformatted text preview: system = 24.0 kg). This yields an acceleration of a = g ( m C − m A )/ M = 1.63 m/s 2 . Next we analyze the forces just on block C : m C g – T = m C a . Thus the tension is T = m C g (2 m A + m B )/ M = 81.7 N....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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