Ch05-p066 - 66 The x direction for m2=1.0 kg is downhill and the x direction for m1=3.0 kg is rightward thus they accelerate with the same sign(a

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66. The + x direction for m 2 =1.0 kg is “downhill” and the + x direction for m 1 =3.0 kg is rightward; thus, they accelerate with the same sign. (a) We apply Newton’s second law to the x axis of each box: 22 1 sin mg T ma FTm a θ −= += Adding the two equations allows us to solve for the acceleration: 2 12 F a mm + = + With F = 2.3 N and 30 , we have a = 1.8 m/s 2 . We plug back and find T = 3.1 N. (b) We consider the “critical” case where the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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