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66. The +
x
direction for
m
2
=1.0 kg is “downhill” and the +
x
direction for
m
1
=3.0 kg is
rightward; thus, they accelerate with the same sign.
(a) We apply Newton’s second law to the
x
axis of each box:
22
1
sin
mg
T
ma
FTm
a
θ
−=
+=
Adding the two equations allows us to solve for the acceleration:
2
12
F
a
mm
+
=
+
With
F
= 2.3 N and
30
=°
, we have
a
= 1.8 m/s
2
. We plug back and find
T
= 3.1 N.
(b) We consider the “critical” case where the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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