This preview shows page 1. Sign up to view the full content.
a
FFF
m
=
−−
=
=
123
2
50
083
N3
0
N1
0
N
12 kg
m/s
..
(c) In this case, the forces
G
G
FF
23
and
are collectively strong enough to have
y
components
(one positive and one negative) which cancel each other and still have enough
x
contributions (in the –
x
direction) to cancel
G
F
1
. Since
G
G
=
, we see that the angle
above the –
x
axis to one of them should equal the angle below the –
x
axis to the other one
(we denote this angle
θ
). We require
()
50 N
30N cos
xx
θθ
−=
+
=
−
−
which leads to
=
F
H
G
I
K
J
=°
−
cos
.
1
50
34
N
60N
71. The goal is to arrive at the least magnitude of
G
F
net
, and as long as the magnitudes of
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details