78. With SI units understood, the net force on the box is ()()netˆˆ3.014 cos 3011 i14 sin305.017 jF=+°−+°+−Gwhich yields net(4.1 N)i(5.0 N)jF=−G.(a) Newton’s second law applied to the m= 4.0 kg box leads to 22(1.0 m/ s )i(1.3 m/ s ) j .Fam==−GG(b) The magnitude of
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.