86. We take the down to be the +ydirection. (a) The first diagram (shown below left) is the free-body diagram for the person and parachute, considered as a single object with a mass of 80 kg + 5.0 kg = 85 kg. GFais the force of the air on the parachute and mgGis the force of gravity. Application of Newton’s second law produces mg– Fa= ma, where ais the acceleration. Solving for Fawe find ()2285 kg 9.8 m/s2.5 m/s
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.