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86. We take the down to be the +
y
direction.
(a) The first diagram (shown below left) is the freebody diagram for the person and
parachute, considered as a single object with a mass of 80 kg + 5.0 kg = 85 kg.
G
F
a
is the force of the air on the parachute and
mg
G
is the force of gravity. Application of
Newton’s second law produces
mg
–
F
a
=
ma
, where
a
is the acceleration. Solving for
F
a
we find
()
22
85 kg 9.8 m/s
2.5 m/s
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force, Mass

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