ch05-p095 - 95 The free-body diagrams is shown on the right...

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Fm g y m,r −= cos θ 0 which produces m, r 579 N y F = . Using the Pythagorean theorem, we find 22 ,, 644 N. xy mr FF += Now, the magnitude of the force exerted on the rider by the motorcycle is the same magnitude of force exerted by the rider on the motorcycle, so the answer is 6.4 × 10 2 N, to two significant figures. 95. The free-body diagrams is shown on the right. Note that m, r y F and m, r x F , respectively, and thought of as the y and x components of the force
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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