Fm
g
y
m,r
−=
cos
θ
0
which produces
m, r
579 N
y
F
=
. Using the Pythagorean theorem, we find
22
,,
644 N.
xy
mr
FF
+=
Now, the magnitude of the force exerted on the rider by the motorcycle is the same
magnitude of force exerted by the rider on the motorcycle, so the answer is 6.4
×
10
2
N,
to two significant figures.
95. The freebody diagrams is shown on the right.
Note that
m, r
y
F
and
m, r
x
F
, respectively, and thought
of as the
y
and
x
components of the force
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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