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()
00
17 N
3.0 s
4.3 m/s.
12 kg
y
yy
y
y
F
vv
a
t
v
t
m
§·
=+=
+
=
=
¨¸
©¹
Thus,
ˆˆ
(5.0m/s)i
(4.3m/s) j .
v
=+
G
(b) We write the position vector of the armadillo as
G
rr
r
xy
##
i
j . At
t
= 3.0 s we have
r
x
= (5.0 m/s) (3.0 s) = 15 m and (using Eq. 215 with
v
0
y
= 0)
2
22
0
11
1
1
7
N
3.0 s
6.4 m.
2
1
2
k
g
y
y
F
rvt a
t
t
m
§·§·
=
=
=
¨¸¨¸
The position vector at
t
= 3.0 s is therefore
(15 m) i
(6.4 m)j .
r
G
97. The coordinate choices are made in the problem statement.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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