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Applying Newton’s second law, we obtain
11
1
22
2
sin
Tm
g
m
a
mg
T
ma
θ
−=
Adding the two equations allows us to solve for the acceleration:
21
mm
ag
θθ
§·
−
=
¨¸
+
©¹
With
1
30
=°
and
2
60
, we have
a
= 0.45 m/s
2
. This value is plugged back into
either of the two equations to yield the tension
T
= 16 N.
99. The +
x
axis is “uphill” for
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 Spring '08
 Any
 Physics, Mass

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