ch06-p005 - / m = s g . Eq. 2-16 then gives the shortest...

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5. The greatest deceleration (of magnitude a ) is provided by the maximum friction force (Eq. 6-1, with F N = mg in this case). Using Newton’s second law, we find a = f s,max
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Unformatted text preview: / m = s g . Eq. 2-16 then gives the shortest distance to stop: | x | = v 2 /2 a = 36 m. In this calculation, it is important to first convert v to 13 m/s....
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