16. (a) We apply Newton’s second law to the “downhill” direction:
mg
sin
θ
–
f
=
ma
,
where, using Eq. 611,
f
=
f
k
=
μ
k
F
N
=
k
mg
cos
θ
.
Thus, with
k
= 0.600, we have
a
=
g
sin
–
k
cos
= –3.72 m/s
2
which means, since we have chosen the positive direction in the direction of motion
(down the slope) then the acceleration vector points “uphill”; it is decelerating.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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