16. (a) We apply Newton’s second law to the “downhill” direction: mgsinθ– f= ma,where, using Eq. 6-11,f=fk=μkFN=kmgcosθ .Thus, with k= 0.600, we havea= gsin– kcos= –3.72 m/s2which means, since we have chosen the positive direction in the direction of motion (down the slope) then the acceleration vector points “uphill”; it is decelerating.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.