This preview shows page 1. Sign up to view the full content.
which we will solve with calculus techniques (to find the angle
φ
m
corresponding to the
maximum mass that can be pulled).
dm
dt
T
g
m
m
s
=−
F
H
G
I
K
J
=
cos
sin
μ
0
This leads to tan
ms
=
which (for
s
=
035
.
) yields
m
=°
19 .
(b) Plugging our value for
m
into the equation we found for the mass of the boxand
sand yields
m
= 340 kg. This corresponds to a weight of
mg
= 3.3
×
10
3
N.
19. Fig. 64 in the textbook shows a similar situation (using
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details