ch06-p019 - 19. Fig. 6-4 in the textbook shows a similar...

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which we will solve with calculus techniques (to find the angle φ m corresponding to the maximum mass that can be pulled). dm dt T g m m s =− F H G I K J = cos sin μ 0 This leads to tan ms = which (for s = 035 . ) yields m 19 . (b) Plugging our value for m into the equation we found for the mass of the box-and- sand yields m = 340 kg. This corresponds to a weight of mg = 3.3 × 10 3 N. 19. Fig. 6-4 in the textbook shows a similar situation (using
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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