Adding up the three equations and using
12
3
,2
mM
mm
M
==
=
, we obtain
2
Mg
– 2
μ
k
Mg
–
Mg
= 5
Ma .
With
a
= 0.500 m/s
2
this yields
k
= 0.372.
Thus, the coefficient of kinetic friction is
roughly
k
= 0.37.
25. Let the tensions on the strings connecting
m
2
and
m
3
be
T
23,
and that connecting
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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