Adding up the three equations and using 123,2mMmmM===, we obtain2Mg– 2μkMg– Mg= 5Ma .With a= 0.500 m/s2this yields k= 0.372. Thus, the coefficient of kinetic friction is roughlyk= 0.37. 25. Let the tensions on the strings connecting m2and m3be T23,and that connecting
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.