Next, we examine the forces just on m3and find F32= m3(a+ μkg) = 147 N. If the algebra steps are done more systematically, one ends up with the interesting relationship: 323(/)FmMF=(which is independent of the friction!). (b) As remarked at the end of our solution to part (a), the result does not depend on the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.