ch06-p030 - 30. The free-body diagrams are shown below. T...

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m A = 10 kg), and mg B G is the force of gravity on block B . θ = 30° is the angle of incline. For A we take the + x to be uphill and + y to be in the direction of the normal force; the positive direction is chosen downward for block B . Since A is moving down the incline, the force of friction is uphill with magnitude f k = μ k F N (where k = 0.20). Newton’s second law leads to sin 0 cos 0 0 kA A NA BB T f ma Fm g mg T ma −+ = = −= = for the two bodies (where a = 0 is a consequence of the velocity being constant). We
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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