ch06-p032

# Ch06-p032 - 32 We use the familiar horizontal and vertical axes for x and y directions with rightward and upward positive respectively The rope is

This preview shows page 1. Sign up to view the full content.

(b) Solving the above equation algebraically for F , with W denoting the weight, we obtain (0.42)(180 N) 76 N . cos sin cos (0.42) sin cos (0.42) sin s s W F μ θ θθ == = ++ + (c) We minimize the above expression for F by working through the condition: 2 (sin cos ) 0 (cos sin ) ss s W dF d + which leads to the result = tan –1 s = 23°. (d) Plugging = 23° into the above result for F , with s = 0.42 and W = 180 N, yields 70 N F = . 32. We use the familiar horizontal and vertical axes for x and y directions, with rightward and upward positive, respectively. The rope is assumed massless so that the force exerted by the child G F is identical to the tension uniformly through the rope. The x and y components of
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online