ch06-p040 - 40. (a) From Table 6-1 and Eq. 6-16, we have vt...

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40. (a) From Table 6-1 and Eq. 6-16, we have v F CA mg v t g t = ¡ = 2 2 2 ρ where v t = 60 m/s. We estimate the pilot’s mass at about m = 70 kg. Now, we convert v = 1300(1000/3600) 360 m/s and plug into Eq. 6-14: DC A v mg v vm g v v tt == F H G I K J = F H G I K J 1 2 1 2 2 2 2 2 2 which yields D = (70 kg)(9.8 m/s 2 )(360/60) 2 2 × 10 4 N. (b) We assume the mass of the ejection seat is roughly equal to the mass of the pilot.
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