ch06-p043 - since the bottom-most point of the car tire is...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
43. Perhaps surprisingly, the equations pertaining to this situation are exactly those in Sample Problem 6-9, although the logic is a little different. In the Sample Problem, the car moves along a (stationary) road, whereas in this problem the cat is stationary relative to the merry-go-around platform. But the static friction plays the same role in both cases
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: since the bottom-most point of the car tire is instantaneously at rest with respect to the race track, just as static friction applies to the contact surface between cat and platform. Using Eq. 6-23 with Eq. 4-35, we find s = (2 R/T ) 2 / gR = 4 2 R/gT 2 . With T = 6.0 s and R = 5.4 m, we obtain s = 0.60....
View Full Document

Ask a homework question - tutors are online