(c) If r= 10 m and v= 12 m/s, we obtain FB= – 2.3 ×103N = – 2.3 kN, or |FB| = 2.3 kN. (d) The minus sign indicates that GFBpoints downward. 50. The situation is somewhat similar to that shown in the “loop-the-loop” example done in the textbook (see Figure 6-10) except that, instead of a downward normal force, we are dealing with the force of the boom GFBon the car – which is capable of pointing any direction. We will assume it to be upward as we apply Newton’s second law to the car (of
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.