centripetal force that keeps the puck in its circular orbit, so T= mv2/r. Thus Mg = mv2/r.We solve for the speed: 2(2.50kg)(9.80m/s )(0.200 m)1.81 m/s.1.50kgMgrvm===55. For the puck to remain at rest the magnitude of the tension force
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.