ch06-p056 - 56. (a) Using the kinematic equation given in...

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56. (a) Using the kinematic equation given in Table 2-1, the deceleration of the car is 22 2 0 2 0 (35 m/s) 2 (107 m) vv a d a =+ ¡ which gives 2 5.72 m/s . a =− Thus, the force of friction required to stop by car is 23 | | (1400 kg)(5.72 m/s ) 8.0 10 N. fm a == × (b) The maximum possible static friction is ,max (0.50)(1400 kg)(9.80 m/s ) 6.9 10 N. ss g μ × (c) If 0.40 k = , then kk f mg = and the deceleration is
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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