with
v
= 60(1000/3600) = 17 m/s and
R
= 200 m. The banking angle is therefore
θ
= 8.1°.
Now we consider a vehicle taking this banked curve at
v'
= 40(1000/3600) = 11 m/s. Its
(horizontal) acceleration is
2
/
av
R
′′
=
, which has components parallel the incline and
perpendicular to it:
2
 
2
cos
cos
sin
sin
.
v
aa
R
v
R
⊥
′
′
==
′
′
These enter Newton’s second law as follows (choosing downhill as the +
x
direction and
awayfromincline as +
y
):

sin
cos
s
N
mg
f
ma
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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