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60. (a) We note that
R
(the horizontal distance from the bob to the axis of rotation) is the
circumference of the circular path divided by 2
π
; therefore,
R
=
0.94/2
= 0.15 m.
The
angle that the cord makes with the horizontal is now easily found:
θ
= cos
−
1
(
R/L
) = cos
−
1
(0.15 m
/
0.90 m) = 80º.
The vertical component of the force of tension in the string is
T
sin
and must equal the
downward pull of gravity (
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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