(c) Either estimating from the graph (
μ
s
= 0.60, upper curve) or calculated it more
carefully leads to
v
= 41.3 m/s = 149 km/h when
θ
= 10º = 0.175 radian.
(d) Similarly (for
s
= 0.050, the lower curve) we find
v
= 21.2 m/s = 76.2 km/h when
=
10º = 0.175 radian.
62. (a) To be on the verge of sliding out means that the force of static friction is acting
“down the bank” (in the sense explained in the problem statement) with maximum
possible magnitude.
We first consider the vector sum
F
→
of the (maximum) static
friction force and the normal force.
Due to the facts that they are perpendicular and their
magnitudes are simply proportional (Eq. 61), we find
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force, Friction

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