Ch06-p063 - 63(a With = 60 we apply Newtons second law to the downhill direction mg sin f = ma f = fk = k FN = k mg cos Thus a = g(sin k cos = 7.5

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63. (a) With θ = 60º, we apply Newton’s second law to the “downhill” direction: mg sin f = ma f = f k = μ k F N = k mg cos . Thus, a = g (sin θ k cos ) = 7.5 m/s 2 . (b) The direction of the acceleration a G is down the slope. (c) Now the friction force is in the “downhill” direction (which is our positive direction)
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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