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63. (a) With θ = 60º, we apply Newton’s second law to the “downhill” direction: mg sin – f = ma f = f k = μ k F N = k mg cos . Thus, a = g (sin θ – k cos ) = 7.5 m/s 2 . (b) The direction of the acceleration a G is down the slope. (c) Now the friction force is in the “downhill” direction (which is our positive direction)
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