212sinkmgfammθ−=+Forfk= μkFN= km1g,we obtain222(3.0 kg)(9.8 m/s )sin30(0.25)(2.0 kg)(9.8 m/s )1.96 m/s3.0 kg 2.0 kga°−==+.Returning this value to either of the above two equations, we find T= 8.8 N. 64. Note that since no static friction coefficient is mentioned, we assume fsis not relevant
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