85. The mass of the car is m= (10700/9.80) kg = 1.09 ×103kg. We choose “inward” (horizontally towards the center of the circular path) as the positive direction. (a) With v= 13.4 m/s and R= 61 m, Newton’s second law (using Eq. 6-18) leads to fmvRs==×23321 10.N.(b) Noting that FN= mgin this situation, the maximum possible static friction is found to
This is the end of the preview. Sign up
access the rest of the document.