85. The mass of the car is m= (10700/9.80) kg = 1.09 ×103kg. We choose “inward” (horizontally towards the center of the circular path) as the positive direction. (a) With v= 13.4 m/s and R= 61 m, Newton’s second law (using Eq. 6-18) leads to fmvRs==×23321 10.N.(b) Noting that FN= mgin this situation, the maximum possible static friction is found to
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.