ch06-p085 - 85. The mass of the car is m = (10700/9.80) kg...

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85. The mass of the car is m = (10700/9.80) kg = 1.09 × 10 3 kg. We choose “inward” (horizontally towards the center of the circular path) as the positive direction. (a) With v = 13.4 m/s and R = 61 m, Newton’s second law (using Eq. 6-18) leads to f mv R s == × 2 3 321 10 .N . (b) Noting that F N = mg in this situation, the maximum possible static friction is found to
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