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Tm
g
mv
R
g
v
R
−=
¡
=+
F
H
G
I
K
J
22
where Eq. 618 has been used. Increasing the speed eventually leads to the tension at the
bottom of the circle reaching that breaking value of 40 N.
(b) Solving the above equation for the speed, we find
2
40 N
(0.91 m)
9.8 m/s
0.37 kg
T
vR
g
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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