89. (a) The push (to get it moving) must be at least as big as f s,max = μ s F N (Eq. 6-1, with F N = mg in this case), which equals (0.51)(165 N) = 84.2 N. (b) While in motion, constant velocity (zero acceleration) is maintained if the push is equal to the kinetic friction force
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.