ch06-p091

ch06-p091 - f k = 311 N(a Here we find F push< f max...

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91. We apply Newton’s second law (as F push f = ma ). If we find F push < f max , we conclude “no, the cabinet does not move” (which means a is actually 0 and f = F push ), and if we obtain a > 0 then it is moves (so f = f k ). For f max and f k we use Eq. 6-1 and Eq. 6-2 (respectively), and in those formulas we set the magnitude of the normal force equal to 556 N. Thus, f max = 378 N and
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Unformatted text preview: f k = 311 N. (a) Here we find F push < f max which leads to f = F push = 222 N. (b) Again we find F push < f max which leads to f = F push = 334 N. (c) Now we have F push > f max which means it moves and f = f k = 311 N. (d) Again we have F push > f max which means it moves and f = f k = 311 N. (e) The cabinet moves in (c) and (d)....
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