Unformatted text preview: path leads to T = mg + mv 2 / r where F N is at its greatest value. (b) At the breaking point T = 33 N = m ( g + v 2 / r ) where m = 0.26 kg and r = 0.65 m. Solving for the speed, we find that the cord should break when the speed (at the lowest point) reaches 8.73 m/s....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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