ch06-p092 - path leads to T = mg mv 2 r where F N is at its...

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92. (a) The tension will be the greatest at the lowest point of the swing. Note that there is no substantive difference between the tension T in this problem and the normal force F N in Sample Problem 6-7. Eq. 6-19 of that Sample Problem examines the situation at the top of the circular path (where F N is the least), and rewriting that for the bottom of the
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Unformatted text preview: path leads to T = mg + mv 2 / r where F N is at its greatest value. (b) At the breaking point T = 33 N = m ( g + v 2 / r ) where m = 0.26 kg and r = 0.65 m. Solving for the speed, we find that the cord should break when the speed (at the lowest point) reaches 8.73 m/s....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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