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96. For the
m
2
= 1.0 kg block, application of Newton's laws result in
2
2
cos
axis
sin
0
axis
k
N
FT
f
m
a
x
FF
m
g
y
θ
−− =
−−
=
Since
f
k
=
μ
k
F
N
, these equations can be combined into an equation to solve for
a
:
22
(cos
sin )
kk
m
g
m
a
μ
−
=
Similarly (but without the applied push) we analyze the
m
1
= 2.0 kg block:
1
1
axis
0
k
N
Tf m
a x
Fm
g
y
′
−=
′
Using
f
k
=
k
N
F
′
,
the equations can be combined:
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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