This simplifies to – 2 g sin θ = a . Eq. 2-16 then gives the distance to stop: Δ x = – v o 2 /2 a . (a) Thus, the distance up the incline traveled by the block is Δ x = v o 2 /(4 g sin ). (b) We usually expect μ s > k (see the discussion in section 6-1). Sample Problem 6-2 treats the “angle of repose” (the minimum angle necessary for a stationary block to start sliding downhill): s = tan( repose ). Therefore, we expect repose > found in part (a). Consequently, when the block comes to rest, the incline is not steep enough to cause it to start slipping down the incline again. 99. Replace f s with f k in Fig. 6-5(b) to produce the appropriate force diagram for the first
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.