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This simplifies to
– 2
g
sin
θ
=
a
. Eq. 216 then gives the distance to stop:
Δ
x
= –
v
o
2
/2
a
.
(a) Thus, the distance up the incline traveled by the block is
Δ
x
=
v
o
2
/(4
g
sin
).
(b) We usually expect
μ
s
>
k
(see the discussion in section 61). Sample Problem 62
treats the “angle of repose” (the minimum angle necessary for a stationary block to start
sliding downhill):
s
= tan(
repose
).
Therefore, we expect
repose
>
found in part (a).
Consequently, when the block comes to rest, the incline is not steep enough to cause it to
start slipping down the incline again.
99. Replace
f
s
with
f
k
in Fig. 65(b) to produce the appropriate force diagram for the first
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration, Force

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